c d .....................................................................\d . THIS IS A TEST TO SEE HOW TO GET AN EVEN DISTRIBUTION .d . OF RANDOM NUMBERS .d . .@e .....................................................................Le A( )Xe B( )^eze "NUMBER OF COUNTS ";Ze# "............................. PLEASE WAIT....."ed .........................GENERATE RAND NUMBER ......................fnfx T ZfA (fB 4fC @fD VfN((ABCD))hf A(N)A(N)pf Tf .................. GENERATE 2ND RAND NUMBER ....................fff Q ZfAA fBB fCC gDD gNN((AABBCCDD))4g" B(NN)B(NN)gHgM M (2,)gR W  g\ (W2,A(W))gf W&h ......................... PLOT 2ND CURVE ...........................,h2hAh M(2,)Qh WW  mh (WW2,B(WW))vh WWh< ................... THE FINAL CURVE ............................... iF . TIS IS THE FINAL TEST IF IT WORKS I SHOULD GET AN .TiP . ALMOST STRAIGHT LINE PLOTTED WHICH WILL MEAN THAT .iZ . NUMBERS THROUGHOUT THE RANGE ARE BEING GENERATED .id . WITH EQUAL FREQUENCY .2jn ...................................................................8jxFj (2,_)Uj L  xj (L2,(B(L)A(L)))j Lj "READY FOR TOTALS ";PPj @j .......................... PLOT GRAPH ...........................jk (0,)k X,Y k Xc +k (X,Y)5k ok 50,170,50,95,48,95,50,95,50,20,150,20,150,18,150,20k 250,20,250,18,99,99k@kJ P  kT "A(";P;")=";A(P);" B(";P;")=";B(P);" AVG=";(B(P)A(P))kYk^ Pkh0,18,99,99k@kJ P  kT "A(";P;")=";A(P);" B(";P